By Michael Sullivan
University Algebra, 9/E
Michael Sullivan, Chicago country University
ISBN-10: 0321716817 • ISBN-13: 9780321716811
©2012 • Pearson • textile, 840 pp
Published 01/04/2011 • Instock
Suggested retail cost: $206.00
Mike Sullivan’s time-tested strategy focuses scholars at the primary talents they want for the path: getting ready for sophistication, practising with homework, and reviewing the ideas. within the 9th version, collage Algebra has advanced to satisfy today’s path wishes, construction on those hallmarks by means of integrating initiatives and different interactive studying instruments to be used within the lecture room or online.
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Extra info for College Algebra (9th Edition)
If c Ú 0, then 11c22 = c. For example, 11222 = 2 and 11322 = 3. 4 ᭹ Examples 11(a) and (b) are examples of square roots of perfect squares, since 1 1 2 64 = 82 and = a b . 16 4 24 CHAPTER R Review Consider the expression 2a2. Since a2 Ú 0, the principal square root of a2 is defined whether a 7 0 or a 6 0. However, since the principal square root is nonnegative, we need an absolute value to ensure the nonnegative result. 3 (c) 4x2 = ƒ x ƒ Now Work ᭹ PROBLEM 83 7 Use a Calculator to Evaluate Exponents Your calculator has either a caret key, ^ , or an xy key, which is used for computations involving exponents.
That is, 10 = 0. 3. The principal square root of a positive number is positive. 4. If c Ú 0, then 11c22 = c. For example, 11222 = 2 and 11322 = 3. 4 ᭹ Examples 11(a) and (b) are examples of square roots of perfect squares, since 1 1 2 64 = 82 and = a b . 16 4 24 CHAPTER R Review Consider the expression 2a2. Since a2 Ú 0, the principal square root of a2 is defined whether a 7 0 or a 6 0. However, since the principal square root is nonnegative, we need an absolute value to ensure the nonnegative result.
Finding the Intersection and Union of Sets Let A = 51, 3, 5, 86, B = 53, 5, 76, and C = 52, 4, 6, 86. 1 Real Numbers Solution (a) A ¨ B = 51, 3, 5, 86 ¨ 53, 5, 76 = 53, 56 (b) A ´ B = 51, 3, 5, 86 ´ 53, 5, 76 = 51, 3, 5, 7, 86 (c) B ¨ 1A ´ C2 = 53, 5, 76 ¨ 351, 3, 5, 86 ´ 52, 4, 6, 864 = 53, 5, 76 ¨ 51, 2, 3, 4, 5, 6, 86 = 53, 56 Now Work PROBLEM ᭹ 13 Usually, in working with sets, we designate a universal set U, the set consisting of all the elements that we wish to consider. Once a universal set has been designated, we can consider elements of the universal set not found in a given set.